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Exercise
Practical 13 - Estimation of Sulphur Dioxide |
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Aim: To estimate the level of sulphur dioxide contents in fruit and vegetable products
Theory and principle: Sulphur dioxide in food product is added as class II preservative and may exists as undissociated sulphurous acid, as free bisulphate or sulphite ions or as combined SO2 in the form of hydroxy sulphonates. Sulphur dioxide is measured as free or total SO2. Estimation of SO2 in squashes, jam, RTS drinks is important as its presence beyond the prescribed FPO limits make the product not confirming to Indian Food Laws. Generally 2 parts of KMS (Potassium metabisulphite) releases one part of SO2 explained as under: SO2 is added in the form of potassium meta-bisulphite (KMS) K2S2O5=2(SO2) +K2O (39x2)+(32x2)+(16x5) = 2(32+32) 78+64+80 = 2(64)
222 = 128
128 x 100 % SO2 in KMS = ------------------- = 57.70% 222 Thus, 1g of KMS releases 0.57g of SO2.Free SO2 is measured by direct titration with iodine. In the estimation of total SO2 the combined SO2 is liberated by treatment with excess alkali at room temperature, subsequent acidification to prevent recombination and titration with iodine. The method used is known as Modified Ripper Titration Method. Reagents, glassware and apparatus required
Calculations: 1 ml of 0.02 N Iodine = 0.64 mg of SO2 Titre × 0.64 × 1000 Free SO2 (ppm) = -------------------------------- Weight of sample Titre × 0.64 × 1000 Total SO2 (ppm) = ------------------------------ Weight of sample Combined SO2 (ppm) = Total SO2 - Free SO2 Problem: 25 g of pineapple squash was analysed for estimation of free, total and bound SO2. The prepared sample was titrated against 0.02N Iodine solution for free SO2 to give a titre value of bound SO2 (a) as 10 ml. The titre for iodine reducing substances other than SO2 (b) was 2.0 ml. For estimation of total sulphur dioxide similar 25 g pineapple squash sample was prepared and titrated against 0.02N NaOH iodine solution. The titre for total iodine reducing substances (c) was recorded as 16 ml while titre for total iodine reducing substances other than sulphites was 4 ml. calculate Free SO2, Total SO2 and Combined SO2 in the pineapple squash. Solution: Free SO2 Weight of sample taken for estimation of free SO2= 25 g Titre value of bound SO2 (a)= 10 ml Titre value of iodine reducing substances other than SO2 (b) = 2 ml a-b= 10-2= 8 ml Titrex0.64x1000 Free SO2 ppm= ------------------------------ wt. of sample
8x 0.64x1000
= --------------------- 25 = 204.8 ppm Total SO2 Weight of sample taken for estimation of total SO2 = 25 g Titre value for total iodine reducing substances (c) = 16 ml Titre value for total iodine reducing substances other than sulphites (d) = 4 ml c-d= 16-4= 12 ml Titrex0.64x1000 Total SO2= -------------------------- Wt. of sample 12x0.64x1000
= ---------------------
25 = 307.2 ppm Bound SO2 = Total SO2- Free SO2 = 307.2-204.8 = 102.4 ppm Inference: The given pineapple squash contained 307.2 ppm Total SO2, 204.8 ppm Free SO2 and 102.4 ppm Bound SO2. |
Last modified: Wednesday, 7 March 2012, 10:51 AM