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Electrical conductivity (EC)
The electrical conductivity (EC) measurement gives the total amount of soluble salts present in the soil and is expressed as milli mhos cm-1 or dS m-1. Principle As the amount of the soluble salts in a solution increases the electrical conductivity also increases. This electrical conductivity is measured in terms of the resistance offered to the flow of current using a conductivity bridge. It is known that solutions offer some resistance to the passage of electric current through them, depending upon the concentration of salts present. Hence EC is measured in terms of electrical resistance between parallel electrodes immersed in the soil suspension of water. In such a system, the solution between the electrodes becomes the electrical conductor to which the physical laws relating to resistance are applicable. The electrical resistance “R” is directly proportional to the distance “L” between the electrodes and inversely proportional to the cross sectional area “A” of the conductor. Hence R = L/ A or R= r x L/ A Where r = proportionality constant known as electrical resistivity If L = 1 cm and A = 1 cm2 then R = r. Where, r is called specific resistivity. Hence specific resistance is the resistance of a conductor 1 cm in length and 1 cm2 in area. Higher the salt content, higher the passage of current and lesser the resistance to the flow of the current. Hence the reciprocal of specific resistivity is called as specific conductivity. Therefore specific conductivity is defined as the conductivity of a solution enclosed in a cell whose electrodes are exactly 1 cm and possess a surface area of 1 cm2. The resistance is expressed as ohms cm-1 and the conductivity is expressed in reciprocal ohms or mhos per cm. It is not possible to make a conductivity bridge having electrodes 1 sq.cm. in area and place exactly 1 cm apart. Hence, the factor called the cell constant is determined for the given cell. Modern conductivity meters are calibrated to read directly the electrical conductance with given cell. Materials required i) Conductivity bridge ii) 100 ml beaker iii) Glass rod iv) 0.01 N KCl solution and v) Saturated CaSO4 solution. Procedure |
Last modified: Thursday, 21 June 2012, 12:24 PM