Henderson-Hasselbalch equation

HENDERSON - HASSELBALCH EQUATION

  • A weak acid HA ionizes as follows

 HA → H+ + A-

  • The equilibrium constant for this reaction is written as follows

Ka = [H+][A-] / [HA]

The value of te dissociation constant (Ka) indicates the tendency of the acid to lose its proton. Stronger acids have a grater tendency to dissociate and therefore have higher dissoiation constant

  • [HA] = concentration of the undissociated acid, [H+] = concentration of hydrogen ion and [A-] = concentration of the conjucate base.
  • Cross multiplying:

[H+][A-] = Ka [HA]

[H+] = Ka * ( [HA] / [A-])

  • Taking -log of both sids

-log [H+] = -log  Ka -log  ( [HA] / [A-] )

  • Substitute pH and pK for -log[H+] and -logK respectively. The -log of the dissociation constant is defined as the pKa.

pH = pKa  -log  ( [HA] / [A-] ) (The stronger the acid ,lower is its pKa)

  • Then to remove the -sign invert the last term

pH = pKa  + log  ( [A-] / [HA] )

  • When the pH is equal to pKa, the concentration of conjugate base is equal to concentration of undissociated acid. 
Last modified: Saturday, 24 December 2011, 6:00 AM