Site pages
Current course
Participants
General
Topic 1
Topic 2
Topic 3
Topic 4
Topic 5
Topic 6
Topic 7
Topic 8
Topic 9
Topic 10
Topic 11
Topic 12
Topic 13
Topic 14
Topic 15
Topic 16
Topic 17
Topic 18
Topic 19
Topic 20
Topic 21
Topic 22
Topic 23
Topic 24
Topic 25
Topic 26
Topic 27
Topic 28
Topic 29
Topic 30
Topic 31
Topic 32
Topic 33
Topic 34
Topic 35
Quartiles
Raw or ungrouped data Where item and item Example 18 Solution 5, 8, 10, 15, 18,25, 30,35,40, 45 = (2.75)th item = 2nd item + (3rd item – 2nd item) = 8+ (10-8) = 8+ x 2 = 8+1.5 = 9.5 = 3 x (2.75)th item = (8.75)th item = 8th item + (9th item – 8th item) = 35+ (40-35) = 35+1.25 = 36.25 Discrete Series Step1: Find cumulative frequencies. Step2: Find Step3: See in the cumulative frequencies , the value just greater than , then the corresponding value of x is Q1 Step4: Find Step5: See in the cumulative frequencies, the value just greater than ,then the corresponding value of x is Q3 Example 19 Compute quartiles for the data given bellow(insects/plant).
Solution
=18.75th item ...Q1= 8; Q3=24 Continuous series Step1: Find cumulative frequencies Step2: Find Step3: See in the cumulative frequencies, the value just greater than , then the corresponding class interval is called first quartile class. Step4: Find See in the cumulative frequencies the value just greater than then the corresponding class interval is called 3rd quartile class. Then apply the respective formulae Where l1 = lower limit of the first quartile class Example 20: The following series relates to the marks secured by students in an examination
|
Last modified: Friday, 16 March 2012, 7:12 PM