Fish Population Dynamic and Stock Assessment (2+1)

Solution

(i) Arrange the length group of species to be studied

(ii) Calculate mid length

(iii) Number of specimens caught for each length group is to be noted.

$$\overline{L}$$ =$$\left( \sum C \ast {{L_2+L_2}\over2}\right )$$ / n 

[45 cm can be taken as smallest length group (L') in this example. Hence, L' is taken as 45]

Z = K . $${L_{\infty}- \overline{L}}\over {\overline{L}-L'}$$