Exercise

Exercise 12: Determination of P2O5 and K2O

Determination of P2O5
Material required
Equipment and glassware
  • Porcelain dish
  • Water bath
  • Beaker (500ml)
  • Shaker
  • Red litmus paper
  • Whatman No. 44 filter paper
Reagent
  • HCl
  • H2SO4
  • HNO3
  • Ammonia solution
  • Molybdate solution
  • Soodium nitrate
  • NaOH
  • Phenolphthalein indicator
Procedure
Preperation of extract
  • Take 20-50 ml of HCl extract in a 50 ml porcelain glazed dish. Evaporate on a water bath and ignite at a dull read heat. Rub with a pestle and ignite again.
  • Extract the well ignited mass with hot water and filter free from chlorides. Keep the residues on the filter paper for the estimation of P2O5 and the extract for potash.
Determination of P2O5
  • Digest the residue from which the potassium is removed for half an hour on a water bath with 30 ml of 10% H2SO4 and filter free from acid.
  • Transfer the filterate to a 400 ml beaker.
  • Add 5-10 ml HNO3 and then add ammonia until a precipitate that forms dissolve on shaking.
  • Dilute to about 100 ml and warm to about 25 – 30oC and put a piece of red litmus paper which should turn blue.
  • Now add drop wise drop HNO3(1+10) till it turns red again. Add sufficient amount (30 ml) of molybdate solution to ensure complete precipitation.
  • Shake vigorously for five minutes, allow to stand for at least half an hour.
  • Filter by decantation using Whatman No. 44 filter paper.
  • Wash the precipitate with 2 % solution of sodium nitrate or ice cold water. The washing should be continued till the filterate is free from acid.
  • It can be tested by adding a drop of standard alkali and a few drops of phenolphthalein.
  • The filterate should have pink colour.
  • Spread the filter paper on the sides of the beaker in which the precipitation was done.
  • Wash it with a jet of distilled water. Dissolve in a known amount of N/10 NaOH.
  • Titrate with N/10 H2SO4, using phenolphthalein indicator till the pink colour just disappears.
  • Put the filter paper in the beaker and add more acid till the pinkish color which reappeared on the addition of filter paper disappears.

Calculate results assuming 1 ml N/10 NaOH = 0.000309 g P2O5

Determination of K2O
Reagent
  • HCl
  • H2SO4
  • Glacial acetic acid
  • Sodium chloride
  • Sodium nitrate
  • Cobalt nitrate
  • Alcohol
  • KMnO4
  • Evaporate the water extract on the water bath after the addition of few drops of HCl
  • When cold take up the residue in 1.5 ml glacial acetic acid and 10 ml of saturated sodium chloride solution.
  • Stir well and after 3 to 4 minutes, add 5 ml of 35% NaNO2 solution stirring again.
  • When solution is complete say after 5-10 minutes, but not longer, add 5ml of 20% cobalt nitrate solution rapidly with constant stirring. It would not take more than 2-3 seconds.
  • Stir for 40 to 60 seconds. Cover and allow it to settle overnight in a cool place free from fumes of ammonia.
  • Filter through a gooch crucible charged with asbestos or use sintered glss crucible No. 4.
  • Transfer the precipitate to the crucible and wash 4 times with 6-10 ml of 35% alcohol each time.
  • Fially wash the sides of the crucible with 3 small lots of about 2 ml each of cold water to remove alcohol.
  • Pipette out a suitable amount i.e. 50 ml of 0.05N KMnO4 in a 400ml beaker.
  • Dilute to about 150 ml with water and add 5 ml of H2SO4(1+10). Add the crucible and the precipitate in this mixture and keep it submerged in the solution warm gently.
  • If the colour appears to be discharged add further known quantity of KMnO4 solution to ensure an excess. Heat nearly to boiling.
  • Remove from the flame and after few minutes add excess of 0.05N oxalic acid (50ml).
  • Warm until all oxides of manganese have dissolved.
  • Titrate excess of oxalic acid with 0.05N KMnO4 used for the oxidation of the precipitate.
Calculations
Amount of 0.25% solution of potassium sulphate taken = 10ml
Amount of 0.05 N KMnO4 solution added = 50ml
Amount of 0.05 N oxalic acid solution added = 50ml
Amount of 0.05 N KMnO4 solution required for the excess of oxalic acid = y ml
Amount of 0.05 N KMnO4 solution used for reacting with precipitate= x- y ml
12.1
Amount of K= Amount of K2O x 72 / 94
Last modified: Wednesday, 14 March 2012, 5:57 AM