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Compass surveying - Problem-2
Unit 1- Surveying
Compass surveyingProblems
2. The following angles were observed in clockwise direction in an open traverse, ∟ABC = 124º 15”, ∟BCD = 156º 30’, ∟CDE = 102º, DEF = 95º, and ∟EFG = 215º 45’
Magnetic bearing of the line AB was 241º 30’ what would be the bearing of the line FG
Bearing of the line BC = Bearing of the line AB+ ∟B + 180º
= 241º 30’ +124º 15’ -180º =185º 45’
Bearing of the line CD = Bearing of the line BC + ∟C+180º
= 185º 45’ +156º 30’-180º =162º 15’
Bearing of the line DE = Bearing of the line CD + ∟D+ 180º
= 162º 15’ + 102º – 180º = 84º 15’
Bearing of the line EF = Bearing of the line D E + ∟E + 180º
= 84º 15’ + 95º 15’ -180º =359º 30’
Bearing of the line FG = Bearing of the line E F + ∟F + 180º
= 359º 30’+215º 45’- 360º - 180º = 35º 15’
Magnetic bearing of the line AB was 241º 30’ what would be the bearing of the line FG
Bearing of the line BC = Bearing of the line AB+ ∟B + 180º
= 241º 30’ +124º 15’ -180º =185º 45’
Bearing of the line CD = Bearing of the line BC + ∟C+180º
= 185º 45’ +156º 30’-180º =162º 15’
Bearing of the line DE = Bearing of the line CD + ∟D+ 180º
= 162º 15’ + 102º – 180º = 84º 15’
Bearing of the line EF = Bearing of the line D E + ∟E + 180º
= 84º 15’ + 95º 15’ -180º =359º 30’
Bearing of the line FG = Bearing of the line E F + ∟F + 180º
= 359º 30’+215º 45’- 360º - 180º = 35º 15’
Last modified: Thursday, 12 May 2011, 5:26 AM