LESSON 17. Design of Singly Reinforced Section

17.1 INTRODUCTION

In singly-reinforced beams we come across the following types of problems:

Type A Data:   Dimensions of the section, permissible stresses in concrete and steel, area of tensile steel and modular ratio.

Required: Moment of resistance of the section.

This type of problem may be solved as follows:

  1. First determine the position of the actual neutral axis by equating the moment of the concrete area in compression about the neutral axis to the moment of equivalent tension area about the neutral axis i.e. use the relation,  171

  2. Find the position of critical neutral axis corresponding to the given safe stresses in concrete and steel.

  3. Ascertain whether the section is under-reinforced or over-reinforced. If the actual neutral axis lies above the critical neutral axis, the section is under-reinforced. But, if the actual neutral axis is below the critical neutral axis, the section is over-reinforced

  4. If the section is over-reinforced concrete attains its permissible stress earlier than steel, and the moment of resistance is given by

172

Taking,                        c = 173= permissible stress in concrete

and                                       n = depth of actual neutral axis.

If the section is under-reinforced, steel attains its permissible stress earlier than concrete and the moment of resistance is given by

                                                M.R. =   174

taking,                                     t =  =  permissible stress in steel

and                                                n  = depth of actual neutral axis.

Type B Data : Dimensions of the section, Area of reinforcement, Bending moment M and modular ratio.

Required : Stresses in concrete and steel.

This type of problem may be solved as follows:

1. Determine the position of the actual neutral axis.

2. Find the stress in concrete by equating the moment of resistance to the given bending moment i.e., use the relation,

175

3. Find the stress in steel from the relation.

 176

Type C Data : Permissible stresses in concrete and steel, Bending moment M and modular ratio.

Required: To design the section.

This type of problem may be solved as follows: The beam will be designed as a balanced section

1.Determine the depth of critical neutral axis in terms of the effective depth d.

177

2. Choose a convenient width b. By equating the moment of resistance to the given bending moment, find the effective depth

178

3. Find the area of steel by equating the total compression on the beam section to the total tension on the beam section.

179

The following problems illustrate the above types of problems.

 

Example 17.1 A singly reinforced beam 250 mm wide and 380 mm deep to the centre of reinforced with 3 bars of 18 mm diameter. Determine the depth of neutral axis and the maximum stress in concrete when the stress in steel is 150 N/mm2. Take m = 13.33.

Solution. 1710

Position of neutral axis (see Fig. 17.1)

17.1 Example 17.1

1711

 

Example 17.2 The cross-section of a singly-reinforced concrete beam is 300 mm wide and 400 mm deep to the centre of the reinforcement which consists of three bars of 12 mm diameters. If the stresses in concrete and steel are not to exceed 7 N/mm2 and 230 N/mm2, determine the moment of resistance of the section. Take m =13.33

Solution.         Area of steel  1712

Position of actual neutral axis (see Fig. 17.2)

17.2 Example 17.2

Taking moments about the neutral axis,

1713

Example 17.3 The cross-section of a singly-reinforced concrete beam is 300 mm wide and 400 mm deep to the centre of the reinforcement which consists of four bars of 16 mm diameter. If the stresses in concrete and steel are not exceed 7 N/mm2 respectively, determine the moment of resistance of the section. Take m = 13.33.

Solution.      1714                      

Position of actual neutral axis (see Fig. 17.3)

17.3 Example 17.3

Taking moments about the neutral axis         

1715

 

Example 17.4 A singly-reinforced rectangular beam 350 mm wide has a span of 6.25 m and carries an all inclusive load of 16.30 kN/m. If the stresses in concrete and steel shall not exceed 7 N/mm2 and 230 N/mm2 find the effective depth and the area of the tensile reinforcement. Take m=13.33.

1716

                             1717

 Example 17.5 A singly reinforced beam has a span of 5 meters and carries a uniformly distributed load of 25 kN/m. The width of the beam is chosen to be 300 mm. Find the depth and the steel area requited for a balanced section. Use M 20 concrete and Fe415 steel

Solution Maximum bending moment M =1718  = 78.125 kNm

The section is a balanced section (see Fig. 17.4).

17.4 Example 17.5

Equating balanced M.R. to bending moment

0.913 bd2 = 0.913 x 300 d2 = 78.123 x 106

Therefore                                     d = 534 mm

Area of steel required = 1719  = 706.7 mm2

Provide 2 bars of 18 mmΦ and 1 bar 16 mmΦ 

Area of steel provided = 2 (254) + 201 = 709 mm2

Overall depth of the beam = 534 + 9 + 25 = 568 mm

Let us provide an overall depth of 570 mm

Actual effective depth = 570-34 = 536 mm

Example 17.6 Design a singly reinforced beam section subjected to a maximum bending moment of 55.35 kNm. The width of the beam may be made two third the effective depth. Use M 20 concrete and Fe415 steel.

1720

1721

Provide b = 300 mm, d = 450 mm

Provide 3 bars of 16 mm of (603 mm2)

Example 17.7 A singly-reinforced concrete beam is 300 mm wide and 450mm deep to the centre of the tensile reinforcement which consists of 4 bars of 16 mm diameter. If the safe stresses in concrete and steel are 7 N/mm2 and 230 N/mm2 respectively, find the moment of resistance of the section. Take m = 13.33.­

Solution.

                                    b = 300 mm, d =450 mm

                                     = 4 x 201 = 804 mm2

Depth of actual Neutral axis

             1722                      

            Therefore                 1723     = 129.9 mm

Depth of actual Neutral axis,

Taking moments about the neutral axis,

1724

Since n>nc the section is over reinforced

            Therefore Concrete attains its safe stress earlier to steel.

            Moment of resistance  = 1725

Example 17.8 A singly-reinforced concrete beam 350 mm wide and 550mm deep to the centre of the tensile reinforcement is reinforced with 3 bars of 18 mm diameter. Find the moment of resistance of the section. What would be the moment of resistance if the reinforcement is changed to 4 bars of 18 mm diameter. Use M 20 concrete and Fe 415 steel.

Solution.         Safe stresses σcbc = 7 N/mm2, σst = 230 N/mm2

Modular ratio,                     1726 

Depth of critical Neutral axis

1727

Case (i) When 3 bars of 18 mm diameter are provided

                                               1728  = 3 x 254 = 762 mm2

Position of actual neutral axis

Taking moments about the neutral axis

                                              1729

                        n2 + 58.057 n – 31931.429 = 0

                                                n = 152mm      But, nc = 158.8 mm

Since n< nc the section is under-reinforced.

Therefore Steel reaches its safe stress earlier to concrete.

Moment of resistance  =  1730

                                     =     87.513 x 106  Nmm = 87.513 kNm

Case(ii) When 4 bars of 18 mm diameter are provided

                                1111     = 4 x 254 = 1016 mm2

Taking moments about the neutral axis,

                                   1731

n2 + 77.409n – 42575.24 = 0

Therefore         n = 171.2 mm But nc = 158.8 mm

Since,  n > nc the section is over reinforced

Therefore Concrete reaches its safe stress earlier to steel

Moment of resistance             1732

                                                = 103.394 x 106  Nmm = 103.394 kNm

Example 17.9 A singly- reinforced concrete beam 300 mm wide has an effective depth of 500 mm, the effective span being 5 m. It is reinforced with 804 mm2 of steel. If the beam carries a total load of 16 kN/m on the whole span, determine the stresses produced in concrete and steel. Take m = 13.33.

Solution. Maximum B.M. for the beam = 1733  = 50 kNm

Position of neutral axis

Taking moments about the neutral axis,

                                                         1734    = 13.33 x 804 (500 – n)

                             n2 + 71.4488n – 35724.4 = 0

Therefore                                                     n= 156.63 mm

                                  Moment of resistance = Bending moment

                    1735

                                                               c = 1736   = 4.75 N/mm2

           Stress in steel =   1737N/mm2

                                  = 138.80 N/mm2

Example 17.10 A singly-reinforced beam 350mm wide and 550mm deep has an effective span of 6 m and carries an all inclusive load of 20 kN/m. The beam is reinforced with 4 bars of 20 mm diameter at an effective cover of 35 mm. Find the maximum stresses produced in concrete and steel. Take m = 13.33.

Solution. Area of steel                       17288  = 4 x 314 = 1256 mm2

Maximum B.M.                                         = 1738= 90 kNm = 90 x 106 Nmm

Position of actual neutral axis

Effective depth                                   d = 550 – 35 = 515 mm

Taking moments about the neutral axis,

                                                            1739

                               n2 + 95.67n – 49270.7 = 0

Solving, we get                                     n = 179.23 mm

Let the maximum compressive stress reached in concrete be c N/mm2

Equating M.R. to the B.M.

           1740

                                                               c = 6.30 N/mm2

Stress in steel                                       1741

Example 17.11 Find the moment of resistance of a singly reinforced beam section 225 mm wide and 350 mm deep to the centre of the tensile reinforcement if the permissible stresses in concrete and steel are 230 N/mm2 and 7N/mm2. The reinforcement consists of 4 bars of 20 mm diameter. What maximum uniformly distributed load this beam can safely carry on a span of 8 m? Take m = 13.33

Solution

                                   1742

Taking moments about the neutral axis (see Fig. 17.5),

17.5 Example 17.11

                                    1743

Therefore                     n2 + 148.893n – 52112.598 = 0

Therefore                     n = 165.67

The depth of critical neutral axis is given by

1744                                    

Since n > nc, the beam section is over reinforced.

Therefore Concrete reaches its permissible stress earlier to steel.

Moment of resistance

                                           1745

                                                = 38458075 Nmm = 38.458 kNm

                                           w = safe uniformly distributed load on the beam

Let maximum bending moment

                                            1746 

Last modified: Saturday, 5 October 2013, 8:22 AM