Calculation

CALCULATION

  • 1cc of 0.01 N NaOH

= 1cc of 0.01 N acetic acid

  • Titer

= 0.01 M. Moles of acetic acid

  • Titer value

= X cc

  • Volume of rumen liquor

= 2 cc

  • For 1000 cc of liquor

= (X x 0.01 x 1000) / 2

= X x 5 = millimoles of VFA/litre

  • Result

= ............ millimoles/Litre

 
Last modified: Saturday, 4 June 2011, 7:15 AM